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= -1: key[i%keylen] = kstream[i] elif key[i%keylen] !

= kstream[i]: #print(i%keylen, i) #print(key) return False # print('tongguo') result = "" for i in key: if i !

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This is a " #m = "AREYOUKIDDINGMEWOCAONIMA" def RCA_crypt(m,keylen): kstream = [ -1 for x in range(256)] j = 0 s = [x for x in range(256)] # print(s) for i in range(256): j = (j s[i] keylen) % 256 s[i], s[j] = s[j], s[i] # exchange i = j = 0 m = list(m) for k in range(len(m)): i = (i 1) % 256 j = (j s[i]) % 256 s[i], s[j] = s[j], s[i] # m[k] = chr(ord(m[k]) ^ kstream[s[(s[i] s[j]) % 256) # print(m[k],c[k]) poss_result = ord(m[k])^ord(c[k]) #print(s[(s[i] s[j]) % 256], chr(poss_result)) if kstream[s[(s[i] s[j]) % 256]] == -1: kstream[s[(s[i] s[j]) % 256]] = poss_result elif kstream[s[(s[i] s[j]) % 256]] !

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e = 4 n1 = 0x5f90c0f7f926dbcdbd0c2b61fc15bf342775889225be93d16c298d062abcf7ed46fa39472890c9c5f40115d2355583638ad57a7c62adeb5f6a697ddd6ad138f124616cd02ba9ca0ae5514c14cdfae0f99d0adf675d2e25642baf18b6903fb3d4afbf0c3b1f13c10ca0ec01b648a3ba0d90d87c5f3a0cece5d5d6c92d85909f09 c1 = 0x3c673bc61e3005e7b07e393fe70a634392f9486caacfca91498cf70b50839a6c2f9d4884678d43b201421432bca61d44e23eea9ad4c0bc28bf7a6fe0fb022fbdeba1e3086f2724c02238d40f11a668eec1a3fa453b0f2c85e0766dcf14b727c07679cbb2ec110f15180921c64a0a1d3971cea2d3b08dc4911c7079c9fecf01ff n2 = 0x66f26c9cc0b2d95c444d9ef5ee21e9994477ab6eaa9268c6b67fc2d02a8609f6afbf9d8133c00fe02f3f8e9abe8067cbc37b720a3e78c822d9bdba84d6a91f27795ae20279904868a9569f67489dbd22f488d615f10723f871c35247802ecfb9cb8ca511acd94868e3dc908903a171fcc3e453172894b534c1b35ef793225dcb c2 = 0x28319d875db93fe2dbf272860eeae88cccc709bd3427c6705656cc4c82092f2185b1a07be4160be93957c83e757fc0a7d2c837722ab2809e8f61abd3eef1a5b160a07309faa2e71529b32fef06413d27109dff86ee82622f549299bc1e40b6eb35b9f2747893258934731a55576cc4cf7a5af90d6a35f5a87fe570a9bda0443b n3 = 0x953791ce9fca97464da25a4a564c7e4f03573a46ec95781f8c13ec46cee6202dcec50e3c37ce4b20b7adf50515cd25f70fbb52a6d24ffda9c95a09c2d18ba9650ba23f4afc4c271e3d3b897f496dbe64622ba0440aaad162494e1553d23edd27d33c0c2004370ba943244916a37ae5e2ab04ddc148cf30aa283adfbbe9320817 c3 = 0x185a5481c3e49bb8cdca66a32003f04d1d3e7ab43a695240ad23423ac80d765b690aa5f338ce1d61fe9dddfe70b09b2751f9bf83bcac5e484fb122fbf253009e9ddd284292f17ec1e133f1f5bc13d8f47576a79da88477b776fe1a3111513098cac1aabb46fe1ad715c48928f907f1e4c02af24c049771f994c7d5dfacf7be2a n4 = 0xcdf98ee3313823c34c61004b38738eb4246890866f63dedf0ee1b85397eb300517b8562e51efca6edb08d579ace07d687588ea82ec2761ce2a7c3a07b8c1afc599a45c018bdc25aa9d3a3dc67ec3d1b7379f6927eb13c8c2b344deeaaee63ff8889bb2233414a10d23d7a1b612956a77d7d98ffaea142c723a3bb6c84842710f c4 = 0xbfdbb23199c0cf57d1472b7dec015b4bf5be5e46b05787d151cbd5f733d0aff4ad77ba858b8ef90b3da165fc79414051a241a462af55668a56df52274a5783d0bc57e8242e9612713bf31fa49ab36c7fc6a81b955bc0ab164fe63f5a65fe1ee9d3b9733321d235eb137d211bec3cade11d3b1e5ca0da0f0b757fb89536e1d7f0 ''' python c1 = 2 n1 = 3 c2 = 3 n2 = 5 c3 = 2 n3 = 7 ''' import gmpy def ex_gcd(a, b): if b == 0: return a, 1, 0 else: g, x, y = ex_gcd(b, a % b) return g, y, x - a // b * y def mod_inv(x, N): g, y, k = ex_gcd(x, N) if (y [email protected]^_\]Z[XYVWT abcdefghijklmnopqrstuvwxyz lonihkjedgfa`cb}|~yx|srqpwvutkjihonmlcba mnohijkdefg`abc|}~xyz{tuv |~yx~xyz{tuvwpqrslmnohijkdef `cbedgfihkjmlonqpsrutwvyx{ # ! ./,-* ()67452301当时还写了一个校验脚本，放在后面把想继续猜下去猜不动了然后有卡住了到第二天，发现一个问题==kstream表是不会变的，变的只是s表，但是s表的改变又只依赖于keylen==，所以如果keylen可以通过明文和密文倒推出kstream，在看能不能倒回去key并且key合不合法，于是开始写脚本，遍历不用keylen能得到的kstrream和key就得到了keylen等于15时的key可以成立，打印出来也挺像样的（下划线是未知的位）Congratulations! This is a modified version of RCfour which tastes much easier. Don't fuck meeeeeeepwergwefcvrhipvhanidoncp wehfowefpjweofjqpf ppoqieuiwygurehfjpsdodiobvudmc fwopjeiimport binascii c = "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" def hex_decode(s): return binascii.a2b_hex(s.encode()).decode() c = hex_decode(c) caide = "Congratulations!

Now that you have solved it, here is the flag 'cnss Brutef Orce ISeff Ic Ientsome TImes'. This is a " tmp = 0 for i in range(len(c)): s = "" for j in 'abcdefghijklmnopqrstuvwxyz': w = chr(ord(c[i]) ^ ord(j)) # if w in "ABCDEFGHIJKLMNPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz": s =w try: if tmp == i and caide[tmp] in s: s = (" " caide[tmp]) else: s = "Wrong" except: pass tmp = 1 # s = w print(s) import binascii def hex_decode(s): return binascii.a2b_hex(s.encode()).decode() c = "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" #c = "2736233b2b37292c25212b2b232824362a2022292f2d2a222723282c2e343325292e2b24" c = hex_decode(c) #print(c) m = "Congratulations!